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There are two shops A and B which sold crackers on Diwali on 3 days – Monday, Tuesday and Wednesday. The average number of crackers A and B sold in the three days is 21 and 25 respectively. The number of crackers shops A sold on Wednesday is double than the number of crackers it sold on Tuesday. The number of crackers A sold on Wednesday is one more than the number of crackers B sold on the same day. B sold 10 more crackers on Tuesday than A. Find the difference in the number of crackers A and B sold on Monday?

There are two shops A and B which sold crackers on Diwali on 3 days – Monday, Tuesday and Wednesday. The average number of crackers A and B sold in the three days is 21 and 25 respectively. The number of crackers shops A sold on Wednesday is double than the number of crackers it sold on Tuesday. The number of crackers A sold on Wednesday is one more than the number of crackers B sold on the same day. B sold 10 more crackers on Tuesday than A. Find the difference in the number of crackers A and B sold on Monday? Correct Answer 3

Given:

The average number of crackers A and B sold in the three days is 21 and 25 respectively. The number of crackers shop A sold on Wednesday is double than the number of crackers it sold on Tuesday. The number of crackers A sold on Wednesday is one more than the number of crackers B sold on the same day. B sold 10 more crackers on Tuesday than A.

Formula:

Average of n numbers a1, a2 ... an = (a1 + a2 + ... an)/n

Calculation:

Two shops A and B sold crackers on Diwali on 3 days – Monday, Tuesday and Wednesday.

Average number of crackers shop A sold in 3 days = 21

Total crackers sold by shop A = 21 × 3 = 63

Similarly, total crackers sold by shop B = 25 × 3 = 75

Monday           Tuesday            Wednesday

A                           x                           2x

B                       x + 10                    2x - 1

Total for shop A = 63

Total for shop B = 75

A Monday = 63 -3x 

B Monday = 75 – (x + 10) – (2x – 1)     

75 – x – 10 – 2x + 1 – 63 + 3x = 3

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