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A car completes a journey of 680 km in 8 hours if the car travels half the distance in 5/8 of the total time. By how much is the speed of the car in the remaining journey is more than the average speed of the car throughout the journey?

A car completes a journey of 680 km in 8 hours if the car travels half the distance in 5/8 of the total time. By how much is the speed of the car in the remaining journey is more than the average speed of the car throughout the journey? Correct Answer (28 + 1/3) km/h

GIVEN:

Total distance = 680 km

Total time = 8 hours

Time taken to cover half distance = 8/5 × total time

FORMULA USED:
Speed = Distance/Time

CALCULATION:

Average speed of journey = 680/8 = 85 km/h

Time taken to cover half distance = 5/8 ×8 = 5 hours

Remaining time = 8 - 5 = 3 hours

Remaining distance = 680/2 = 340 kms

Speed for remaining journey = 340/3 = (113 + 1/3)km/h

Required difference = (113 + 1/3) - 85 = (28 + 1/3) km/h

∴ The answer is (28 + 1/3) km/h.

 

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