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Three cars start from point A together and reach point B at equal intervals. Second car whose sped is less than third car but more than first car taken a u turn and starts its journey towards A whereas third car heads for point C which is 100 km away from point B. First car and third car meet each other at mid way of A and C after third car takes u turn from C. First car travels half the distance between A and B when second reaches B. The sum of speed of second car and third car is 100 kmh.  What is the difference between speed of third car and first car?

Three cars start from point A together and reach point B at equal intervals. Second car whose sped is less than third car but more than first car taken a u turn and starts its journey towards A whereas third car heads for point C which is 100 km away from point B. First car and third car meet each other at mid way of A and C after third car takes u turn from C. First car travels half the distance between A and B when second reaches B. The sum of speed of second car and third car is 100 kmh.  What is the difference between speed of third car and first car? Correct Answer 40 km/h

Calculation:

Let the speed of the first car be V1, the second car be V2 and the third car be V3.

Let the distance between A and B = X

⇒ X/ 2V1 = X/ V2

⇒ V2 = 2V1

Total distance of A to C = 100 + X

Distance covered by third car = 100 + X + ((100 + X)/ 2)

⇒ 100 + X/ 2 V1 = 3(100 + X)/ 2V3

⇒ 1/ V1 = 3/ V3

⇒ V3 = 3 × V1

⇒ V1 + V2 + V3 = 100

⇒ V1 + 2V1 + (3 × V1) = 120

⇒ 6V1 = 120

⇒ V1 = 20 and V3 = 60

⇒ V3 – V1 = 40 km/h

∴ The difference between the speed of the first car and the third car is 40 km/h

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