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In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: A man covered 158 km which is half of the total distance in 3 hrs. 18 min. and completed the remaining journey at a speed of 45 km/hr. Find the average speed of his journey. Quantity B: A train completes a journey of 480 km in 10 hrs. 45 min. If the train halted for a total time of 30 min. in the whole journey, find the average speed of the train.

In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: A man covered 158 km which is half of the total distance in 3 hrs. 18 min. and completed the remaining journey at a speed of 45 km/hr. Find the average speed of his journey. Quantity B: A train completes a journey of 480 km in 10 hrs. 45 min. If the train halted for a total time of 30 min. in the whole journey, find the average speed of the train. Correct Answer Quantity A > Quantity B

Solving for Quantity A:

Speed in the first part = 158/(3 + 18/60) = 47.88 km/hr.

The average speed of two speeds ‘x’ km/hr and ‘y’ km/hr = 2xy/(x + y) km/hr

Required average speed = (2 × 45 × 47.88)/(45 + 47.88) = 46.4 km/hr.

⇒ Quantity A = 46.4 km/hr

Solving for Quantity B:

Distance travelled = 480 km

Time travelled = 10 + (45/60) + (30/60) = 11.15 hrs.

Average speed = 480/11.15 = 43.04 km/hr

⇒ Quantity B = 43.04 km/hr

∴ Quantity A > Quantity B

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