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Doctors Medicines MCQs Q&A

In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: A fruit seller sold 40% of his apples at a price of Rs. 80 per kg. Then he sold 30% of the remaining apples at a price of Rs. 100 per kg. Later, he sold 75% of the remaining apples for Rs. 120 per kg, and further remaining apples at Rs. 60 per kg. If he earned a total of Rs. 11762.50 from selling all his apples, how many apples did he have? Quantity B: 20% of the fruits in a shop are apples, while 40% of the remaining fruits are bananas. Also, 50% of the remaining fruits are mangoes. If the remaining fruits are 16 kg of pineapples and 20 kg of grapes, how many kg fruits are there in the shop?

In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and choose the correct option. Quantity A: A fruit seller sold 40% of his apples at a price of Rs. 80 per kg. Then he sold 30% of the remaining apples at a price of Rs. 100 per kg. Later, he sold 75% of the remaining apples for Rs. 120 per kg, and further remaining apples at Rs. 60 per kg. If he earned a total of Rs. 11762.50 from selling all his apples, how many apples did he have? Quantity B: 20% of the fruits in a shop are apples, while 40% of the remaining fruits are bananas. Also, 50% of the remaining fruits are mangoes. If the remaining fruits are 16 kg of pineapples and 20 kg of grapes, how many kg fruits are there in the shop? Correct Answer Quantity A < Quantity B

Solving for Quantity A:

Let the fruit seller had ‘x’ kg of apples

Apples sold for Rs. 80 per kg = 40% of x = 0.4x

Apples sold for Rs. 100 per kg = 30% of (x - 0.4x) = 0.3 × 0.6x = 0.18x

Apples sold for Rs. 120 per kg = 75% of (x - 0.4x - 0.18x) = 0.75 × 0.42x = 0.315x

Apples sold for Rs. 60 per kg = x - (0.4x + 0.18x + 0.315x) = 0.105x

Now,

Total earning = (80 × 0.4x) + (100 × 0.18x) + (120 × 0.315x) + (60 × 0.105x)

⇒ 11762.5 = 32x + 18x + 37.8x + 6.3x

⇒ 11762.5 = 94.1x

⇒ x = 11762.5/94.1 = 125 kg

⇒ Quantity A = 125 kg

Solving for Quantity B:

Let there be ‘x’ kg of fruits in the shop

Apples = 20% of x = 0.2x

Bananas = 40% of (x - 0.2x) = 0.4 × 0.8x = 0.32x

Mangoes = 50% of (x - 0.2x - 0.32x) = 0.5 × 0.48x = 0.24x

Remaining fruits = x - (0.2x + 0.32x + 0.24x) = 0.24x

⇒ 0.24x = 16 + 20

⇒ x = 36/0.24 = 150 kg

⇒ Quantity B = 150 kg

∴ Quantity A < Quantity B

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