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In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and chose the correct option. Quantity A: The average speed of a car is \(2\frac{3}{5}\) times the average speed of bus. A bike covers 270 km in 3 hour. How much distance will the car cover in 5 hours if the speed of the bus is one third of the speed of bike? Quantity B: The average speed of a train is \(1\frac{4}{7}\) times the average speed of car. The car covers a distance of 490 km in 5 hours. How much distance will the train cover in 10 hours?

In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for the both quantities and chose the correct option. Quantity A: The average speed of a car is \(2\frac{3}{5}\) times the average speed of bus. A bike covers 270 km in 3 hour. How much distance will the car cover in 5 hours if the speed of the bus is one third of the speed of bike? Quantity B: The average speed of a train is \(1\frac{4}{7}\) times the average speed of car. The car covers a distance of 490 km in 5 hours. How much distance will the train cover in 10 hours? Correct Answer Quantity A < Quantity B

Solvin for Quantity A:

Average speed of car = (13/5) × average speed of bus

Speed of bike = distance travel/time taken = 270/3 = 90 km/hr

Speed of bus = (1/3) × 90 = 30 km/hr

Speed of car = (13/5) × 30 = 78 km/hr

Distance cover by car in 5 hours = 78 × 5 = 390 km

Solving for Quantity B:

Average speed of train = (11/7) × average speed of car

Speed of car = 490/5 = 98 km/hr

Speed of train = (11/7) × 98 = 154 km/hr

Distance cover by train in 10 hours = 154 × 10 = 1540 km

∴ Quantity A < Quantity B

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