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A mixture of Alcohol and water weighing 90 liters contains 11.11% alcohol. How much alcohol should be added to make the quantity of water and alcohol is equal?

A mixture of Alcohol and water weighing 90 liters contains 11.11% alcohol. How much alcohol should be added to make the quantity of water and alcohol is equal? Correct Answer 70

Given:

Alcohol is 11.11% in 90 liters mixture.

Calculation:

Alcohol and water weighing 90 liters contains 11.11% alcohol.

Alcohol : water = 90 × (1/9) : 90 × (1/8)                

⇒ Alcohol : water = 10 liters : 80 liters

Let the alcohol added in the mixture be x liters.

⇒ (10 + x)/80 = 1/1

⇒ x = 80 - 10

⇒ x = 70

∴ Alcohol should be added 70 liters.

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