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A mixture of alcohol and water weighing 121 liters contains 9.09% alcohol. How much alcohol should be added to make the quantity of alcohol and water in the ratio 1 : 2 ?

A mixture of alcohol and water weighing 121 liters contains 9.09% alcohol. How much alcohol should be added to make the quantity of alcohol and water in the ratio 1 : 2 ? Correct Answer 44 liters

Given:

Alcohol is 9.09% in 121 liters mixture.

Calculation:

Alcohol and water weighing 121 liters contain 9.09% alcohol.

Alcohol : water = 121 × (1/11) : 121 × (10/11)                

Alcohol : water = 11 : 110

Let the alcohol added in the mixture be x litres.

Alcohol : Water = (11 + x)/110 = 1/2

⇒ 22 + 2x = 110

⇒ 2x = 110 – 22

⇒ 2x = 88

⇒ x = 44

∴ Alcohol should be added 44 litres.

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9.09% → 1/11  

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