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Election for a constituency was conducted in two phases where three contestants A, B and C contested. In first phase 48% of the total voters voted out which A and B got 32% and 46% of the votes (remaining to C). In the next phase where 75% of the remaining people voted A and B got 43% and 33% of the votes casted (Remaining to C). If the amount of votes obtained by A in phase 1 is less than the total votes obtained by B in phase 1 and C in phase 2 by 16080, then what is the total number of voters in the constituency?

Election for a constituency was conducted in two phases where three contestants A, B and C contested. In first phase 48% of the total voters voted out which A and B got 32% and 46% of the votes (remaining to C). In the next phase where 75% of the remaining people voted A and B got 43% and 33% of the votes casted (Remaining to C). If the amount of votes obtained by A in phase 1 is less than the total votes obtained by B in phase 1 and C in phase 2 by 16080, then what is the total number of voters in the constituency? Correct Answer 100000

Let the total number of votes be ‘x’.

Number of voters in phase 1 = 48/100 × x = 0.48x

Number of voters in phase 2 = 75/100 × (100 – 48) /100 × x = 0.39x

Number of voters who voted for A in phase 1 = 32/100 × 0.48x = 0.1536x

Number of voters who voted for B in phase 1 = 46/100 × 0.48x = 0.2208x

Number of voters who voted for C in phase 2 = (100 – 43 – 33) /100 × 0.39x = 0.0936x

Difference between votes for A in phase and (votes for B in phase 1 and vote for C in phase 2) = 0.2208x + 0.0936 – 0.1536x

⇒ 0.1608x

⇒ 16080

∴ x = 100000

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