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A can do a piece of work in 20 days and B can do the same piece of work in 30 days. A and B started the work together in the first 10 days A worked with half of his efficiency and so does B. Now in how many days does the remaining work get completed when both of them work with their full efficiency?

A can do a piece of work in 20 days and B can do the same piece of work in 30 days. A and B started the work together in the first 10 days A worked with half of his efficiency and so does B. Now in how many days does the remaining work get completed when both of them work with their full efficiency? Correct Answer 7 days

Suppose the total work = 60 Units

Efficiency of A = 60/20 = 3 units/days

Efficiency of B = 60/30 = 2 units/days

Given that A and B started work together but with half of their efficiency

1.5 + 1 = 2.5 units /days total efficiency of A and B

Work completed = 10 × 2.5 = 25 units

Work left = (60 - 25) = 35 units

Now they work with their full efficiency

Total efficiency = (3 + 2) = 5 units/days

∴ No. of days taken by A and B together = 35/5 = 7 days

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