A piece of work can be completed by a man in 66 days. The same work can be completed by two women together in the same time and the same work can be completed by three kids together in the same time. If 1 man, 1 woman, and 1 kid work together then in how many days the work will be completed?

A piece of work can be completed by a man in 66 days. The same work can be completed by two women together in the same time and the same work can be completed by three kids together in the same time. If 1 man, 1 woman, and 1 kid work together then in how many days the work will be completed? Correct Answer 36

GIVEN:

1 man or 2 women or 3 kids can complete a piece of work in 66 days each.

FORMULA USED:

Time = Work/Efficiency

CALCULATION:

Let the efficiency of man, woman and kid be m, w and k

According to the question,

1m = 2w = 3k

Ratio of efficiencies of men, women and kid is 6 : 3 : 2

Total work = 6 × 66 = 396

Work done be all together in 1 day = 6 + 3 + 2 = 11 units

Required number of days = 396/11 = 36 days

∴ If 1 man, 1 woman, and 1 kid work together then in 36 days the work will be completed.

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Suppose total work is 66 units.

Efficiency of a man = 66/66 = 1

Efficiency of a women = 66/(66 × 2) = 1/2

Efficiency of a kid = 66/(66 × 3) = 1/3

Time in which all of them will complete the work = 66/(1 + 1/2 + 1/3)

⇒ 66/(11 / 6)

⇒ 36 days

∴ If 1 man, 1 woman, and 1 kid work together then in 36 days the work will be completed.

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