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In an examination, 75% students passed from school A. The number of students appeared from school B is 20% more than that of A and the total number of students who passed the examination is 40% more than the number of students passed from A. What is the percentage of students passed from both schools to those who appeared from B?

In an examination, 75% students passed from school A. The number of students appeared from school B is 20% more than that of A and the total number of students who passed the examination is 40% more than the number of students passed from A. What is the percentage of students passed from both schools to those who appeared from B? Correct Answer 87.5

Let number of students appeared in exam from school A be x.

Number of students from school A who passed the exam = 75/100 × x = 0.75x

Number of students appeared in exam from school B = x + 20% of x = 1.2x

Total number of students from both schools who passed the exam = 0.75x + 40% of 0.75x = 1.05x

Required percentage = 1.05x/1.2x × 100 = 87.5%

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