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A certain number of students from school X appeared in an examination and 20% students failed. From school Y, 130% more students than that from school X, appeared in the same examination. If 90% of the total number of students appeared from both the schools passed, then what is the percentage of students from school Y who failed (correct to one decimal place)?

A certain number of students from school X appeared in an examination and 20% students failed. From school Y, 130% more students than that from school X, appeared in the same examination. If 90% of the total number of students appeared from both the schools passed, then what is the percentage of students from school Y who failed (correct to one decimal place)? Correct Answer 5.7%

Given:

Students failed in school X = 20%

Number of students in school Y = 130% more than the number of students in school X

Students passed in both school = 90%

Calculation:

Let the number of students in school X be 100x

Number of failed students in school X = 20% of 100x

⇒ 20x

Number of passed students in school Y = (100x – 20x) = 80x

Number of students in school Y = 100x + 130% of 100x

⇒ 100x + (130/100 × 100x)

⇒ 100x + 130x

⇒ 230x

Total number of students in school X and school Y = (100x + 230x)

⇒ 330x

Number of passes students in both school = 90% of 330x

⇒ (90/100 × 330)

⇒ 297x

So, number of passed students in school Y = (297x – 80x)

⇒ 217x

Number of failed students in school Y = (230x – 217x)

⇒ 13x

Percentage of failed students in school Y = (13x/230x) × 100

⇒ (1300x/230x)

⇒ 5.65% ~ 5.7%

∴  The percentage of students who failed from school Y is 5.7%

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