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Chemical mixtures X consist of chemicals A and B in ratio of 1 : 3, Chemical Y consist of chemicals A and B in ratio of 3 : 2. Chemical X is present in vessel whose capacity is 2 / 5 times that of vessel in which chemical Y is present. Both the chemicals X and Y are mixed in a large container. What is % of concentration is present in final mixture as A?

Chemical mixtures X consist of chemicals A and B in ratio of 1 : 3, Chemical Y consist of chemicals A and B in ratio of 3 : 2. Chemical X is present in vessel whose capacity is 2 / 5 times that of vessel in which chemical Y is present. Both the chemicals X and Y are mixed in a large container. What is % of concentration is present in final mixture as A? Correct Answer 50%

Given:

Chemical X → chemical A: Chemical B = 1: 3

Chemical Y → Chemical A: Chemical B = 3: 2

Chemical X = 2/5 × chemical Y

Calculation:

Chemical X: Chemical Y = 2 : 5

Now, Let chemical X be 2X litres and Y be 5X litres in final mixture

⇒ Parts of A in final mixture = (2X × 1/ 4) + (5X × 3/ 5)

⇒ Parts of A in final mixture = (X/ 2) + (3X)

⇒ Parts of A in final mixture = 7X/ 2

⇒ Total quantity of final mixture = 7X

⇒ Percentage of concentration = ((7X/ 2)/ (7X)) × 100

∵ Percentage of concentration is 50%

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