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Two people contested in a municipal election in which only 80% of the population were polled. Out of the polled votes, the valid votes was 91%. If the winning candidate got 10% more votes than the losing candidate, what is the percentage of people who voted in favour of the winning candidate out of the total population of the municipality?

Two people contested in a municipal election in which only 80% of the population were polled. Out of the polled votes, the valid votes was 91%. If the winning candidate got 10% more votes than the losing candidate, what is the percentage of people who voted in favour of the winning candidate out of the total population of the municipality? Correct Answer 38.2%

Calculation:

Let m be the votes got by the losing candidate,

Total votes got by the winning candidate = (110/100) × m = 1.1m

Total number of votes polled = (80/100) × P = 0.8P

Total number of valid votes = (91/100) × (0.8P) = 0.728P

Which is also equal to m + 1.1m = 2.1m

⇒ 2.1m = 0.728P

⇒ m = 0.347 P

Percentage of people who voted in favour of winning candidate = (1.1m/P) × 100

⇒  ((1.1 × 0.347P)/P) × 100 ≈ 38.2%

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