The pull required to shear off a rivet, in double shear, per pitch length is

According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length)

A

$$\frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

B

$$1.875 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

C

$$2 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

D

$$3 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

When the axis of load lies in the plane of rivet group, then the most heavily loaded rivet will be the one which (where, Fa is the load shared by each rivet due to axial load and Fm is the shearing load due to moment in any rivet.)

A

Is at the maximum distance from CG of the rivet group

B

Is at the minimum distance from CG of the rivet group

C

Gives the maximum angle between the two forces Fa and Fm

D

Gives the minimum angle between the two forces Fa and Fm

Tearing resistance required to tear off the plate per pitch length is (where p = Pitch of rivets, d = Dia. of rivet hole and $${\sigma _{\text{t}}}$$ = Permissible tensile stress for plate material)

A

$${\text{pd}}{\sigma _{\text{t}}}$$

B

$${\text{pt}}{\sigma _{\text{t}}}$$

C

$$\left( {{\text{p}} - {\text{d}}} \right){\sigma _{\text{t}}}$$

D

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{t}}}$$

The pull required to crush the rivet per pitch length is

A

$${\text{pt}}{\sigma _{\text{t}}}$$

B

$${\text{dt}}{\sigma _{\text{c}}}$$

C

$$\frac{\pi }{4}{{\text{d}}^2}{\sigma _{\text{t}}}$$

D

$$\frac{\pi }{4}{{\text{d}}^2}{\sigma _{\text{c}}}$$

The pull required to tear off the plate per pitch length is (where p = Pitch of rivets, t = Thickness of plates and $${\sigma _{\text{t}}},\,\tau $$ and $${\sigma _{\text{c}}}$$ = Permissible tensile, shearing and crushing stresses respectively)

A

$$\left( {{\text{p}} - 2{\text{d}}} \right){\text{t}} \times {\sigma _{\text{c}}}$$

B

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times \tau $$

C

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$

D

$$\left( {2{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$

In order to avoid tearing off the plate at an edge, the distance from the center of the rivet hole to the nearest edge of the plate (i.e. margin) should be (where d = Diameter of rivet hole in mm)

A

d

B

1.5 d

C

2 d

D

2.5 d

Crushing resistance required to crush the rivet per pitch length is

A

$${\text{pd}}{\sigma _{\text{c}}}$$

B

$${\text{pt}}{\sigma _{\text{c}}}$$

C

$${\text{ndt}}{\sigma _{\text{c}}}$$

D

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{c}}}$$

A triple riveted butt joint with double straps of unequal width is to be designed for a boiler shell. The pitch of the rivets in the outer row is double the pitch in the inner row and zigzag riveting is proposed. Which of the following statement is correct?

A

There are four rivets per pitch length, all in double shear

B

There are four rivets per pitch length, out of which two are in single shear and two are in double shear

C

There are five rivets per pitch length, all in double shear

D

There are five rivets per pitch length, out of which four are in double shear and one is in single shear

In order to avoid tearing of the plate at edge, the distance from the center line of the rivet hole to the nearest edge of the plate in terms of dia. of rivet d should be equal to

A

1 d

B

1.25 d

C

1.5 d

D

1.75 d

According to Indian standards, the diameter of rivet hole is made larger than the basic size of rivet by

A

0.5 mm up to rivet diameter of 24 mm

B

1 mm for rivet diameter from 27 mm to 36 mm

C

2 mm for rivet diameter from 39 mm to 48 mm

D

All of the above

The pull required to shear off a rivet, in double shear, per pitch length is

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