Tearing resistance required to tear off the plate per pitch length is (where p = Pitch of rivets, d = Dia. of rivet hole and $${\sigma _{\text{t}}}$$ = Permissible tensile stress for plate material)

The pull required to tear off the plate per pitch length is (where p = Pitch of rivets, t = Thickness of plates and $${\sigma _{\text{t}}},\,\tau $$ and $${\sigma _{\text{c}}}$$ = Permissible tensile, shearing and crushing stresses respectively)

A

$$\left( {{\text{p}} - 2{\text{d}}} \right){\text{t}} \times {\sigma _{\text{c}}}$$

B

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times \tau $$

C

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$

D

$$\left( {2{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$

If number of rivets subjected to single shear per pitch length is 2 and those subjected to double shear per pitch length are 3, then find the shear resistance of rivets is diameter of rivets is 20mm and permissible shear 60N/mm².

A

None of the listed

B

146.1kN

C

150.7kN

D

140.2kN

In order to avoid tearing of the plate at edge, the distance from the center line of the rivet hole to the nearest edge of the plate in terms of dia. of rivet d should be equal to

A

1 d

B

1.25 d

C

1.5 d

D

1.75 d

In order to avoid tearing off the plate at an edge, the distance from the center of the rivet hole to the nearest edge of the plate (i.e. margin) should be (where d = Diameter of rivet hole in mm)

A

d

B

1.5 d

C

2 d

D

2.5 d

A riveted joint may fail by 1. tearing of the plate at an edge 2. tearing of the plate across a row of rivets 3. shearing of rivets Which of the above are correct?

A

1 and 2 only

B

1 and 3 only

C

2 and 3 only

D

1, 2 and 3

Which of the following assumptions are made in the design of rivet joints? A. Rivets are stressed equally B. Stress in plate is maximum at mid-width C. Rivet hole is completely filled by rivet D. Friction between plates is neglected

A

only A

B

A and C only

C

B and D only

D

A, C and D only

In order to avoid tearing of the plate at an edge, the distance from the centre line of the rivet hole to the nearest edge of the plate should be equal to (where d = Diameter of rivet hole)

A

1 d

B

1.5 d

C

2.5 d

D

2 d

According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length)

A

$$\frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

B

$$1.875 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

C

$$2 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

D

$$3 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

Two plates are joined by double strap butt joints with rivets arrangement as shown in the figure. Width of the plate is 300mm and diameter of rivets 30mm. The thickness of the plates can be taken as 20mm. Allowable stress in tension, shear and compression are 80 N/mm²,60 N/mm² and 160N/mm². If width of plate=80mm and diameter of rivets 10mm, then pitch will be?

A

65mm

B

60mm

C

50mm

D

70mm

A plate with an elliptical hole in the centre, with semi-major axis (a) perpendicular to the direction of loading and semi-minor axis (b) along the direction of loading, is subjected to a pull P. The maximum stress induced at the edge of the hole is equal to (where $$\sigma $$ = Stress for a plate with no hole i.e. nominal stress)

A

$$\sigma \left( {1 + \frac{{\text{b}}}{{2{\text{a}}}}} \right)$$

B

$$\sigma \left( {1 + \frac{{2{\text{a}}}}{{\text{b}}}} \right)$$

C

$$\sigma \left( {1 + \frac{{\text{b}}}{{3{\text{a}}}}} \right)$$

D

$$\sigma \left( {1 + \frac{{3{\text{a}}}}{{\text{b}}}} \right)$$

Tearing resistance required to tear off the plate per pitch length is (where p = Pitch of rivets, d = Dia. of rivet hole and $${\sigma _{\text{t}}}$$ = Permissible tensile stress for plate material)

Related Questions