Tearing resistance required to tear off the plate per pitch length is (where p = Pitch of rivets, d = Dia. of rivet hole and $${\sigma _{\text{t}}}$$ = Permissible tensile stress for plate material)

A $${\text{pd}}{\sigma _{\text{t}}}$$
B $${\text{pt}}{\sigma _{\text{t}}}$$
C $$\left( {{\text{p}} - {\text{d}}} \right){\sigma _{\text{t}}}$$
D $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{t}}}$$

Correct Answer: $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{t}}}$$

Bissoy MCQ
#Mechanical Engineering #Machine Design

Related Questions

The pull required to tear off the plate per pitch length is (where p = Pitch of rivets, t = Thickness of plates and $${\sigma _{\text{t}}},\,\tau $$  and $${\sigma _{\text{c}}}$$ = Permissible tensile, shearing and crushing stresses respectively)
A $$\left( {{\text{p}} - 2{\text{d}}} \right){\text{t}} \times {\sigma _{\text{c}}}$$
B $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times \tau $$
C $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$
D $$\left( {2{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$
In order to avoid tearing of the plate at edge, the distance from the center line of the rivet hole to the nearest edge of the plate in terms of dia. of rivet d should be equal to
A 1 d
B 1.25 d
C 1.5 d
D 1.75 d
In order to avoid tearing off the plate at an edge, the distance from the center of the rivet hole to the nearest edge of the plate (i.e. margin) should be (where d = Diameter of rivet hole in mm)
A d
B 1.5 d
C 2 d
D 2.5 d
In order to avoid tearing of the plate at an edge, the distance from the centre line of the rivet hole to the nearest edge of the plate should be equal to (where d = Diameter of rivet hole)
A 1 d
B 1.5 d
C 2.5 d
D 2 d
According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length)
A $$\frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
B $$1.875 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
C $$2 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
D $$3 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
A plate with an elliptical hole in the centre, with semi-major axis (a) perpendicular to the direction of loading and semi-minor axis (b) along the direction of loading, is subjected to a pull P. The maximum stress induced at the edge of the hole is equal to (where $$\sigma $$ = Stress for a plate with no hole i.e. nominal stress)
A $$\sigma \left( {1 + \frac{{\text{b}}}{{2{\text{a}}}}} \right)$$
B $$\sigma \left( {1 + \frac{{2{\text{a}}}}{{\text{b}}}} \right)$$
C $$\sigma \left( {1 + \frac{{\text{b}}}{{3{\text{a}}}}} \right)$$
D $$\sigma \left( {1 + \frac{{3{\text{a}}}}{{\text{b}}}} \right)$$
To avoid the tearing off the plate of an edge, the margin (i.e., the minimum distance from the centre of the rivet hole to the nearest edge of the plate) should be equal to
A 0.5 d
B D
C 1.5 d
D 2.5 d
When the axis of load lies in the plane of rivet group, then the most heavily loaded rivet will be the one which (where, Fa is the load shared by each rivet due to axial load and Fm is the shearing load due to moment in any rivet.)
A Is at the maximum distance from CG of the rivet group
B Is at the minimum distance from CG of the rivet group
C Gives the maximum angle between the two forces Fa and Fm
D Gives the minimum angle between the two forces Fa and Fm
If the rivets in adjacent rows are staggered and the outermost row has only one rivets, the arrangement of the rivets is called
A Chain riveting
B Zigzag riveting
C Diamond riveting
D Crisscross riveting
When a body is subjected to biaxial stress i.e. direct stresses ($${\sigma _{\text{x}}}$$) and ($${\sigma _{\text{y}}}$$) in two mutually perpendicular planes accompanied by a simple shear stress ($${\tau _{{\text{xy}}}}$$ ), then maximum shear stress is
A $$\frac{1}{2}\sqrt {{{\left( {{\sigma _{\text{x}}} - {\sigma _{\text{y}}}} \right)}^2} + 4\tau _{{\text{xy}}}^2} $$
B $$\frac{1}{2}\sqrt {{{\left( {{\sigma _{\text{x}}} + {\sigma _{\text{y}}}} \right)}^2} + 4\tau _{{\text{xy}}}^2} $$
C $$\sqrt {{{\left( {{\sigma _{\text{x}}} - {\sigma _{\text{y}}}} \right)}^2} + \tau _{{\text{xy}}}^2} $$
D $$\sqrt {{{\left( {{\sigma _{\text{x}}} + {\sigma _{\text{y}}}} \right)}^2} + \tau _{{\text{xy}}}^2} $$

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