According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length)

A $$\frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
B $$1.875 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
C $$2 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$
D $$3 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

Correct Answer: $$1.875 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

Bissoy MCQ
#Mechanical Engineering #Machine Design

Related Questions

When the axis of load lies in the plane of rivet group, then the most heavily loaded rivet will be the one which (where, Fa is the load shared by each rivet due to axial load and Fm is the shearing load due to moment in any rivet.)
A Is at the maximum distance from CG of the rivet group
B Is at the minimum distance from CG of the rivet group
C Gives the maximum angle between the two forces Fa and Fm
D Gives the minimum angle between the two forces Fa and Fm
Tearing resistance required to tear off the plate per pitch length is (where p = Pitch of rivets, d = Dia. of rivet hole and $${\sigma _{\text{t}}}$$ = Permissible tensile stress for plate material)
A $${\text{pd}}{\sigma _{\text{t}}}$$
B $${\text{pt}}{\sigma _{\text{t}}}$$
C $$\left( {{\text{p}} - {\text{d}}} \right){\sigma _{\text{t}}}$$
D $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{t}}}$$
The pull required to tear off the plate per pitch length is (where p = Pitch of rivets, t = Thickness of plates and $${\sigma _{\text{t}}},\,\tau $$  and $${\sigma _{\text{c}}}$$ = Permissible tensile, shearing and crushing stresses respectively)
A $$\left( {{\text{p}} - 2{\text{d}}} \right){\text{t}} \times {\sigma _{\text{c}}}$$
B $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times \tau $$
C $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$
D $$\left( {2{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$
The pull required to shear off a rivet, in double shear, per pitch length is
A $$\frac{\pi }{4}{{\text{d}}^2}{\sigma _{\text{t}}}$$
B $$\frac{\pi }{4}{{\text{d}}^2}\tau $$
C $$\frac{\pi }{2}{{\text{d}}^2}{\sigma _{\text{t}}}$$
D $$\frac{\pi }{2}{{\text{d}}^2}\tau $$
If the rivets in adjacent rows are staggered and the outermost row has only one rivets, the arrangement of the rivets is called
A Chain riveting
B Zigzag riveting
C Diamond riveting
D Crisscross riveting
A triple riveted butt joint with double straps of unequal width is to be designed for a boiler shell. The pitch of the rivets in the outer row is double the pitch in the inner row and zigzag riveting is proposed. Which of the following statement is correct?
A There are four rivets per pitch length, all in double shear
B There are four rivets per pitch length, out of which two are in single shear and two are in double shear
C There are five rivets per pitch length, all in double shear
D There are five rivets per pitch length, out of which four are in double shear and one is in single shear
Minimum pitch of the rivets shall not be less than (where d is gross diameter of rivet)
A 1.5 d
B 2.0 d
C 2.5 d
D 3.0 d
In order to avoid tearing off the plate at an edge, the distance from the center of the rivet hole to the nearest edge of the plate (i.e. margin) should be (where d = Diameter of rivet hole in mm)
A d
B 1.5 d
C 2 d
D 2.5 d
According to I.B.R., the distance between the rows of rivets, for equal number of rivets in more than one row for lap joint or butt joint (chain riveting) shall not be less than
A d
B 1.5 d
C 2 d
D 2.5 d
Crushing resistance required to crush the rivet per pitch length is
A $${\text{pd}}{\sigma _{\text{c}}}$$
B $${\text{pt}}{\sigma _{\text{c}}}$$
C $${\text{ndt}}{\sigma _{\text{c}}}$$
D $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{c}}}$$

Next steps