The pull required to crush the rivet per pitch length is

When the axis of load lies in the plane of rivet group, then the most heavily loaded rivet will be the one which (where, Fa is the load shared by each rivet due to axial load and Fm is the shearing load due to moment in any rivet.)

A

Is at the maximum distance from CG of the rivet group

B

Is at the minimum distance from CG of the rivet group

C

Gives the maximum angle between the two forces Fa and Fm

D

Gives the minimum angle between the two forces Fa and Fm

Crushing resistance required to crush the rivet per pitch length is

A

$${\text{pd}}{\sigma _{\text{c}}}$$

B

$${\text{pt}}{\sigma _{\text{c}}}$$

C

$${\text{ndt}}{\sigma _{\text{c}}}$$

D

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{c}}}$$

According to I.B.R., shearing resistance required to shear off the rivet per pitch length (in double shear) is (where n = Number of rivets per pitch length)

A

$$\frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

B

$$1.875 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

C

$$2 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

D

$$3 \times \frac{\pi }{4}{{\text{d}}^2} \times \tau \times {\text{n}}$$

The pull required to shear off a rivet, in double shear, per pitch length is

A

$$\frac{\pi }{4}{{\text{d}}^2}{\sigma _{\text{t}}}$$

B

$$\frac{\pi }{4}{{\text{d}}^2}\tau $$

C

$$\frac{\pi }{2}{{\text{d}}^2}{\sigma _{\text{t}}}$$

D

$$\frac{\pi }{2}{{\text{d}}^2}\tau $$

Tearing resistance required to tear off the plate per pitch length is (where p = Pitch of rivets, d = Dia. of rivet hole and $${\sigma _{\text{t}}}$$ = Permissible tensile stress for plate material)

A

$${\text{pd}}{\sigma _{\text{t}}}$$

B

$${\text{pt}}{\sigma _{\text{t}}}$$

C

$$\left( {{\text{p}} - {\text{d}}} \right){\sigma _{\text{t}}}$$

D

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{t}}}$$

The pull required to tear off the plate per pitch length is (where p = Pitch of rivets, t = Thickness of plates and $${\sigma _{\text{t}}},\,\tau $$ and $${\sigma _{\text{c}}}$$ = Permissible tensile, shearing and crushing stresses respectively)

A

$$\left( {{\text{p}} - 2{\text{d}}} \right){\text{t}} \times {\sigma _{\text{c}}}$$

B

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times \tau $$

C

$$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$

D

$$\left( {2{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$

When the pitch of the rivet joints is p, what will be the row pitch Pr for chain riveting?

A

Pr = 0.2p

B

Pr = 0.1p

C

Pr = 0.5p

D

Pr = 0.8p

If the thickness of plate to be connected by a rivet is 16 mm, then suitable size of rivet as per Unwin’s formula will be

A

16 mm

B

20 mm

C

24 mm

D

27 mm

What is the efficiency of joint when strength of bolt per pitch length is 60kN and strength of plate per pitch length is 150kN?

A

25%

B

30%

C

35%

D

40%

If number of rivets subjected to single shear per pitch length is 2 and those subjected to double shear per pitch length are 3, then find the shear resistance of rivets is diameter of rivets is 20mm and permissible shear 60N/mm².

A

None of the listed

B

146.1kN

C

150.7kN

D

140.2kN

The pull required to crush the rivet per pitch length is

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