Related Questions

If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is
A $${\text{D}} = \frac{{{\text{W}}\left( {{\text{a}} - {\text{b}}} \right)}}{{4{{\text{a}}^2}{\text{bq}}}}$$
B $${\text{D}} = \frac{{{\text{W}}\left( {{{\text{a}}^2} - {{\text{b}}^2}} \right)}}{{4{{\text{a}}^2}{\text{bq}}}}$$
C $${\text{D}} = \frac{{{\text{W}}\left( {{{\text{a}}^2} - {{\text{b}}^2}} \right)}}{{8{{\text{a}}^2}{\text{bq}}}}$$
D $${\text{D}} = \frac{{{\text{W}}\left( {{{\text{a}}^2} - {{\text{b}}^2}} \right)}}{{4{\text{abq}}}}$$
To ensure that the hogging bending moment at two points of suspension of a pile of length L equals the sagging moment at its centre, the distances of the points of suspension from either end, is
A 0.107 L
B 0.207 L
C 0.307 L
D 0.407 L
A shaft of diameter D is subjected to a twisting moment (T) and a bending moment (M). If the maximum bending stress is equal to maximum shear stress developed, then M is equal to
A $$\frac{{\text{T}}}{2}$$
B T
C 2T
D 4T
When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to
A $$\frac{1}{2}\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
B $$\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
C $$\frac{1}{2}\left( {{\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} } \right)$$
D $${\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
If W is total load per unit area on a panel, D is the diameter of the column head, L is the span in two directions, then the sum of the maximum positive bending moment and average of the negative bending moment for the design of the span of a square flat slab, should not be less than
A $$\frac{{{\text{WL}}}}{{12}}{\left( {{\text{L}} - \frac{{2{\text{D}}}}{3}} \right)^2}$$
B $$\frac{{{\text{WL}}}}{{10}}{\left( {{\text{L}} + \frac{{2{\text{D}}}}{3}} \right)^2}$$
C $$\frac{{{\text{WL}}}}{{10}}{\left( {{\text{L}} - \frac{{2{\text{D}}}}{3}} \right)^2}$$
D $$\frac{{{\text{WL}}}}{{12}}{\left( {{\text{L}} - \frac{{\text{D}}}{3}} \right)^2}$$
The bending moment at a section tends to bend or deflect the beam and the internal stresses resist its bending. The resistance offered by the internal stresses, to the bending, is called
A Compressive stress
B Shear stress
C Bending stress
D Elastic modulus
When a series of wheel loads crosses a simply supported girder, the maximum bending moment under any given wheel load occurs when
A The centre of gravity of the load system is midway between the centre of span and wheel load under consi-deration
B The centre of span is midway between the centre of gravity of the load system and the wheel load under consideration
C The wheel load under consideration is midway between the centre of span and the centre of gravity of the load system
D None of the above
If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by
A $${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}\left( {{\text{c}} - {\text{a}}} \right)}}{4}$$
B $${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}{{\left( {{\text{b}} - {\text{a}}} \right)}^2}}}{4}$$
C $${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}{{\left( {{\text{b}} - {\text{a}}} \right)}^2}}}{8}$$
D $${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}\left( {{\text{b}} + {\text{a}}} \right)}}{8}$$
A shaft is subjected to bending moment M and a torque T simultaneously. The ratio of the maximum bending stress to maximum shear stress developed in the shaft, is
A $$\frac{{\text{M}}}{{\text{T}}}$$
B $$\frac{{\text{T}}}{{\text{M}}}$$
C $$\frac{{2{\text{M}}}}{{\text{T}}}$$
D $$\frac{{2{\text{T}}}}{{\text{M}}}$$
The bending moment ‘M’ and a torque ‘T’ is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then ‘M’ is equal to
A $$\frac{{\text{T}}}{2}$$
B 1T
C 2T
D 4T

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