A shaft of diameter D is subjected to a twisting moment (T) and a bending moment (M). If the maximum bending stress is equal to maximum shear stress developed, then M is equal to

When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to

A

$$\frac{1}{2}\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$

B

$$\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$

C

$$\frac{1}{2}\left( {{\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} } \right)$$

D

$${\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$

Consider the following statements: The basic reason why shafts are made of steel and its alloys is: 1. The shaft is subjected to normal stress. 2. The shaft stress alternates with respect to time. 3. The shaft is subjected to pure compressive stress. 4. The shaft is subjected to the stress of constant intensity. Which of these statements are correct?

A

1 and 2

B

2 and 3

C

3 and 4

D

4 and 1

A shaft is subjected to bending moment M and a torque T simultaneously. The ratio of the maximum bending stress to maximum shear stress developed in the shaft, is

A

$$\frac{{\text{M}}}{{\text{T}}}$$

B

$$\frac{{\text{T}}}{{\text{M}}}$$

C

$$\frac{{2{\text{M}}}}{{\text{T}}}$$

D

$$\frac{{2{\text{T}}}}{{\text{M}}}$$

A shaft is subjected to fluctuating loads for which the normal torque (T) and bending moment (M) are 1000 N-m and 500 N-m respectively. If the combined shock and fatigue factor for bending is 1.5 and combined shock and fatigue factor for torsion is 2, then the equivalent twisting moment for the shaft is

A

2000 N-m

B

2050 N-m

C

2100 N-m

D

2136 N-m

Tresca or maximum-shear stress criteria assumes that yielding occurs when the maximum shear stress reaches a value of the shear stress in the uniaxial tension test. Assume the principal stress being σ1, σ2, σ3 where σ1 is largest, and σ3 is the smallest principal stresses. Find the value of minimum shear stress to cause yielding, given that yield stress in tension is equal to σo?

A

τ = σo

B

τ = σo/2

C

τ = σo/3

D

τ = σo/4

The bending moment ‘M’ and a torque ‘T’ is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then ‘M’ is equal to

A

$$\frac{{\text{T}}}{2}$$

B

1T

C

2T

D

4T

If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 10⁵ N/mm²) when subjected to a twisting moment, produces maximum shear stress of 50 N/mm², the angle of twist in radians, is

A

0.001

B

0.002

C

0.0025

D

0.003

A shaft is subjected to a maximum bending stress of 80 N/mm² and maximum shearing stress equal to 30 N/mm² at a particular section. If the yield point in tension of the material is 280 N/mm² and the maximum shear stress theory of failure is used, then the factor of safety obtained will be

A

2.5

B

2.8

C

3.0

D

3.5

The layout of a shaft supported on bearings at A & B is shown. Power is supplied by means of a vertical belt on pulley B which is then transmitted to pulley C carrying a horizontal belt. The angle of wrap is 180’ and coefficient of friction is 0.3. Maximum permissible tension in the rope is 3kN. The radius of pulley at B & C is 300mm and 150mm. If allowable shear stress in the shaft is 70N/mm² and torsional and bending moments are M=1185000N-mm and m=330000N-mm, find the diameter of the shaft.

A

36.8mm

B

39.7mm

C

44.7mm

D

40.3mm

A flange mounted shear pin is used on a shaft as a safety device. The steel shear pin has a diameter of 2.38 mm and is to be mounted on the flange of shaft rotating at 650 rpm. The maximum power transmitted by the shaft is 4.5 KW. If the shear strength of material of pin is 30 MPa, the radial distance of its mounting is ____

A

5.02 mm

B

11.98 mm

C

47.94 mm

D

301.20 mm

A shaft of diameter D is subjected to a twisting moment (T) and a bending moment (M). If the maximum bending stress is equal to maximum shear stress developed, then M is equal to

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