When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to

A $$\frac{1}{2}\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
B $$\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$
C $$\frac{1}{2}\left( {{\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} } \right)$$
D $${\text{M}} + \sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$

Correct Answer: $$\sqrt {{{\text{M}}^2} + {{\text{T}}^2}} $$

Bissoy MCQ
#Mechanical Engineering #Machine Design

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