If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is

Based on punching shear consideration, the overall depth of a combined footing under a column A, is

A

$$\frac{{{\text{Area of the column A}} \times {\text{Safe punching stress}}}}{{{\text{Load on column A}}}}$$

B

$$\frac{{{\text{Perimeter of column A}} \times {\text{Safe punching stress}}}}{{{\text{Load on column A}} + {\text{Upward pressure}} \times {\text{Area of column}}}}$$

C

$$\frac{{{\text{Perimeter of column A}} \times {\text{Safe punching stress}}}}{{{\text{Load on column A}} \times {\text{Upward pressure}} \times {\text{Area of column}}}}$$

D

None of these

The length of each side of square A is increased by 100 percent to make square B. Again the length of each side of square B is increased by 50 percent to make square C. By what percent is the area of square C greater than the sum of the areas of square A and B?

A

75%

B

80%

C

85%

D

90%

If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by

A

$${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}\left( {{\text{c}} - {\text{a}}} \right)}}{4}$$

B

$${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}{{\left( {{\text{b}} - {\text{a}}} \right)}^2}}}{4}$$

C

$${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}{{\left( {{\text{b}} - {\text{a}}} \right)}^2}}}{8}$$

D

$${\text{B}}{\text{.M}}{\text{.}} = \frac{{{\text{pb}}\left( {{\text{b}} + {\text{a}}} \right)}}{8}$$

The length of each of square A is increased by 100 percent to make square B.Again the length of the each side of square B is increased by 50 peacent to make square C.By of the area df square A and B?

A

75%

B

80%

C

85%

D

90%

Weight of C is twice the weight of M. Weight of M is 1/9 of the weight of R. Weight of R is 5/2 of the weight of K. Weight of K is 1/3 of the weight of G. Who is the second lightest?

A

C

B

M

C

K

D

G

If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is

A

$${\text{h}} = \frac{{\text{W}}}{{{\text{Aw}}}}\left$$

B

$${\text{h}} = \frac{{\text{W}}}{{{\text{Aw}}}}\left$$

C

$${\text{h}} = \frac{{\text{W}}}{{{\text{Aw}}}}{\left^2}$$

D

$${\text{h}} = \sqrt {\frac{{\text{W}}}{{{\text{Aw}}}}} {\left^2}$$

The length of a rectangle is 6 feet more than the side of a square and the width of the rectangle is 6 feet less than the side of that square. If the area of the square is 64 sq feet, what is the area of the rectangle?

A

20 sq feet

B

30 sq feet

C

40 sq feet

D

28 sq feet

The length of a rectangle is 6 cm more than the side of a square, and the width of the rectangle is 6 cm less than the side of the square. If the area of the square is 86 cm2. what is the area of the rectangle?

A

36 cm2

B

40 cm2

C

50 cm2

D

64 cm2

A small square region inside a larger square is shaded. The diagonal of the larger square is three times the diagonal of the small square in length. What fraction of the area of the larger square is not shaded?

A

1/9

B

1/3

C

2/3

D

8/9

A swimming pool is initially filled to a depth of 96 inches. After 2 weeks, the depth has decreased to9212 inches. Assuming that the depth decreased at a constant rate, after how many days would the water depth have reached 9334 inches?

A

3

B

9

C

7

D

6

If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is

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