In a Davis steering gear, the distance between the pivots of the front axle is 1.2 metres and the wheel base is 2.7 metres. Find the inclination of the track arm to the longitudinal axis of the car, when it is moving along a straight path.

In a Davis steering gear, the distance between the pivots of the front axle is 1.2 metres and the wheel base is 2.7 metres. Find the inclination of the track arm to the longitudinal axis of the car, when it is moving along a straight path. Correct Answer 12.5°

c = 1.2 m ; b = 2.7 m Let α = Inclination of the track arm to the longitudinal axis. We know that tan α = c/2b = 1.2/2 x 2.7 or, α = 12.5°.

Related Questions

Each of the question below consists of a question and three statements number I, II and III given below it. You have to decide whether the data provided in the statement are sufficient to answer the question. If the bus is travelling from Surat to Ahmadabad and a car is travelling from Ahmadabad to Surat, then what is the distance between Surat and Ahmadabad? I. The speed of a car is 40% less than the speed of bus. Bus started at 9 am and car started at 10 am and they meet at 3 pm of the same day. II. After travelling for 1 hour, because of traffic average speed of bus is decreased by 20% and covers distance between Surat to Ahmadabad in 11 hours. Original speed of car is 20% less than original speed of bus and before crossing bus it covered 200 km if starts 1 hour later than bus. After crossing car, bus covers remaining distance in 5 hours. III. Speed of bus is 10 km/hr more than the speed of car and before crossing car ratio of distances covered bus and car in same time was 5 : 4. Time taken by car to cover the distance between Ahmadabad and Surat is 2 hours 15 minutes more than time taken by bus to cover the same distance.
The fundamental equation for correct steering is (where $$\varphi $$ and $$\alpha $$ = Angle through which the axis of the outer wheel and inner wheel turns respectively, c = Distance between the pivots of the front axles and d = Wheel base)
A car travels along a path A-B-C-D (along segments AB, BC and CD). Points A, B, C, D are equidistant from each other, what was the speed of the car while travelling in the segment CD? I. The total distance covered by the car is 288 km and the speed of the car in segment BC is 72 km/h. II. The average speed of the car during the entire Journey is 72 km/h. The speed of the car to cover segments AB, BC and CD Is in the ratio of 15 : 12 : 10 respectively.