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A container contains 100 liters mixture, in which there is 20% Whisky. Find the quantity of pure Whisky to be added in it to make the solution contain 50% Whisky

A container contains 100 liters mixture, in which there is 20% Whisky. Find the quantity of pure Whisky to be added in it to make the solution contain 50% Whisky Correct Answer 60 litres

Given:

Mixture =.100 litres

Percent of  Whisky in the container = 20%

Calculation:

Quantity of  Whisky = 100 × 20%

⇒ Quantity of  Whisky = 20 litres

Let the added quantity of  Whisky be x litre.

After adding x litre of Whisky,

Total quantity of  Whisky = x + 20

Total quantity of container mixture = x + 100

According to the question,

⇒ {(x + 20)/(x + 100)} × 100 = 50%

⇒ {(x + 20)/(x + 100)} = 1/2

⇒ 2x + 40 = x + 100

⇒ x = 60

∴ The added quantity of the  Whisky is 60 litres.

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