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When 12 litres of water were added with some quantity of pure watermelon juice then the ratio of juice to water become 5 : 4 Quantity I: In the mixture, when 2 litres of pure watermelon juice are added then what will be the concentration of juice in the new mixture?  Quantity II: Instead of 12 litres of water, if 5 litres of water were added and the quantity of pure watermelon juice remained the same then what would be the concentration of pure watermelon juice  in the mixture?

When 12 litres of water were added with some quantity of pure watermelon juice then the ratio of juice to water become 5 : 4 Quantity I: In the mixture, when 2 litres of pure watermelon juice are added then what will be the concentration of juice in the new mixture?  Quantity II: Instead of 12 litres of water, if 5 litres of water were added and the quantity of pure watermelon juice remained the same then what would be the concentration of pure watermelon juice  in the mixture? Correct Answer Quantity 1 < Quantity 2

Given:

Ratio of juice to water = 5 : 4

Water = 12 L

Calculations:

Let the quantity of pure watermelon juice = 5x litres and quantity of water = 4x litres

⇒ 4x = 12 litres

⇒ x = 3 litres

⇒ the quantity of pure milk = 5x

⇒ 5 × 3 = 15 litres

Quantity I:

In the mixture, when 2 litres of pure watermelon juice are added then the quantity of pure juice = 15 + 2 = 17 litres ⇒ The quantity of mixture = 17 + 12 = 29 litres

⇒ The concentration of watermelon juice = (15 × 100) / 29

⇒ The concentration of watermelon juice  ≈ 51.7%

∴ concentration of watermelon juice  ≈ 52%

Quantity II:

Instead of 12 litres of water, if 5 litres of water were added and the quantity of pure juice remained the same then the quantity of pure juice = 15 litres, the quantity of water = 5 litres

⇒ the quantity of mixture = 15 + 5 = 20 litres

⇒ required concentration = 15 × 100/20

⇒ required concentration = 75%

∴ Quantity I < Quantity II

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