If side length of cube changing at `0.1mm//sec`. Then what will be rate of change of volume, when side length is 2 meter
If side length of cube changing at `0.1mm//sec`. Then what will be rate of change of volume, when side length is 2 meter
A. `8xx10^(-4)m^(3)//sec`
B. `4xx10^(-3)m^(3)//sec`
C. `12xx10^(-4)m^(3)//sec`
D. `12xx10^(-3)m^(3)//sec`
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Correct Answer - C
`v=l^(3)`
`(dv)/(dt)=3l^(2)((dl)/(dt))`
`((dv)/(dt))=3(2)^(2)(10^(-4)m^(3)//sec)`
`((dv)/(dt))=12xx10^(-4)m//sec`
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