The time period of an oscillator is `8` sec. the phase difference from `t = 2` sec to `l = 4` sec will be :-

Question

The time period of an oscillator is `8` sec. the phase difference from `t = 2` sec to `l = 4` sec will be :-

The time period of an oscillator is `8` sec. the phase difference from `t = 2` sec to `l = 4` sec will be :-
A. `pi`
B. `(pi)/(2)`
C. `(pi)/(4)`
D. `2pi`

Monjur Alahi

20 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`(DeltaT)/(T) = (Deltaphi)/(2pi) rArr 2/8 = (Deltaphi)/(2pi) rArr Deltaphi = pi/2`

20 views Answered 2023-02-05 15:29