Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period
Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period .
6 views
1 Answers
`T = ("Total time")/("Total oscillation") = (t)/(10)`
`rArr DeltaT = (Deltat)/(10) = (0.1)/(10)`
`DeltaT = 0.01` second .
6 views
Answered