A paricle performs `S.H.M.` with time period `T`. The time taken by the particle to move from hall the amplitude to the maximum dispalcement is `T/2`
A. `T/2`
B. `T/4`
C. `T/6`
D. `T/8`

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Correct Answer - C
Required time `= T/4 - T/12 = T/6`

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