The equation of particle executing simple harmonic motion is `x = (5m) sin [(pis^(-1))t+(pi)/(3)]`. Write down the amplitude, time period and maximum

Question

The equation of particle executing simple harmonic motion is `x = (5m) sin [(pis^(-1))t+(pi)/(3)]`. Write down the amplitude, time period and maximum

The equation of particle executing simple harmonic motion is `x = (5m) sin [(pis^(-1))t+(pi)/(3)]`. Write down the amplitude, time period and maximum speed. Also find the velocity at `t = 1 s`.

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Comparing with equation `x = Asin (omegat + delta)`.
we see that amplitude `= 5 m`, and the period `= (2pi)/(omega) = (2pi)/(pis^(-1)) = 2s`.
The velocity at time `t = (dx)/(dt) = Aomegacos(omegat + delta)`
At `t = 1 s`,
`v = (5m)(pis^(-1))cos(pi + (pi)/(3)) = -(5pi)/(2) m//s`

5 views Answered 2023-02-05 15:29