If 0.224 L of `H_(2)` gas is formed at the cathode, the volume of `O_(2)` gas formed at the anode under identical conditions, is:

Question

If 0.224 L of `H_(2)` gas is formed at the cathode, the volume of `O_(2)` gas formed at the anode under identical conditions, is:

If 0.224 L of `H_(2)` gas is formed at the cathode, the volume of `O_(2)` gas formed at the anode under identical conditions, is:
A. 0.224 L
B. 0.448 L
C. 0.112 L
D. 1.12L

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Equivalent of `H_(2)=` equivalence of `O_(2)`
`(0.224)/(22.4)xx2=("volume of "O_(2))/(22.4)xx4`
`0.112` litre `="volume of " O_(2)`

5 views Answered 2023-02-05 15:29