On electrolysis of brine solution, the amounts of NAOH and `Cl_(2)` produced at cathode and anode respectively are :

Question

On electrolysis of brine solution, the amounts of NAOH and `Cl_(2)` produced at cathode and anode respectively are :

On electrolysis of brine solution, the amounts of NAOH and `Cl_(2)` produced at cathode and anode respectively are :
A. 40 parts and 35.5 parts
B. 35.5 parts and 40 parts
C. 100 parts and 80 parts
D. 80 parts and 100 parts

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
Equivalent mass of NAOH = 40
Equivalent mass of `Cl_(2) = 35.5`
Thus, on electrolysis of brine we will get 40 parts of NAOH at cathode and 35.5 parts of `Cl_(2)` at anode.

5 views Answered 2023-02-05 15:29