`1L` of `1M CuSO_(4)` solution is electrolyzed using `Pt` cathode and `Cu` anode. After passing `2F` of electricity, the `[Cu^(2+)]` will be
`1L` of `1M CuSO_(4)` solution is electrolyzed using `Pt` cathode and `Cu` anode. After passing `2F` of electricity, the `[Cu^(2+)]` will be
A. `M//2`
B. `M//4`
C. `M`
D. zero
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Correct Answer - D
2F charge will deposit 2 equivalent or 1 mole of copper
`Cu^(2+)+2e^(-) rarr Cu`
Thus, all the copper from `CuSO_(4)` solution will be deposied and molarity of remaining `CuSO_(4)` solution will be zero.
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