1 gram of carbonate `(M_(2)CO_(3))` on treatment with excess HCl produces 0.1186 mole of `CO_(2)`. The molar mass of `M_(2)CO_(3) "in g mol"^(-1)`

Question

1 gram of carbonate `(M_(2)CO_(3))` on treatment with excess HCl produces 0.1186 mole of `CO_(2)`. The molar mass of `M_(2)CO_(3) "in g mol"^(-1)`

1 gram of carbonate `(M_(2)CO_(3))` on treatment with excess HCl produces 0.1186 mole of `CO_(2)`. The molar mass of `M_(2)CO_(3) "in g mol"^(-1)`
A. 1186
B. 84.3
C. 118.6
D. 11.86

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

The standard enthalpies of formation of `CO_(2)(g), H_(2)O(l)` and glucose (s) at `25^(@)C` are `-400` kJ/mol, `-300` kJ/mol and `-1300` kJ/mol, respe

2 Answers 4 Views

A reaction at 300 K with `DeltaG^(@)` `=- 1743 J//mol` consister of 3 mole of A(g), mole of B(g) and 3 mole of C (g). If A, B and C(g) . If A,B and C

2 Answers 5 Views

Calculate the molecular mass of a substance, 1.0 gram of which when dissolved in 100 gram of solvent gace an elecation of 0.307 K in the boiling point

2 Answers 10 Views

A solution containing 15 g of urea (Molar mass =60 g `mol^(-1)`) per litrea has the same osmotic presure (isotonic) as a solution of glucose (molar ma

2 Answers 6 Views

A 5% solution of cane sugar (molar mass = 342) is isotonic with 1% solution os a substance X. The molar mass of X is:

2 Answers 6 Views

1.0 g of a non-electolyte solute (molar mass 250 g `mol^(-1)`) was dissolved in 51.2 g of benzene. If the `K_(f)` for benzene is 5.12 K kg `mol^(-1)`,

2 Answers 4 Views

Assertion : A solution which contains one gram mole of the solute dissolved per litre of the solution is called molar solution. Reason : A normal solu

2 Answers 5 Views

If 10g of A(molar mass = 20g) reacts with 30g of B(molar mass = 30 g) according to following steps. Step-I `A+3BrarrC+2D` Step-II `D+2Erarr5F` Calcula

2 Answers 5 Views

For 0.2 mol `C_(3)H_(4)` and 0.5 mol `C_(2)H_(6)` gas mixture? Mass of mixture is 23 g It includes 1.6 mol C atom It includes `0.7 xx 6.022 xx 10^(23)

2 Answers 8 Views

One mole of an organic amide (A) on alkaline hydrolysis gives one mole of `NH_(3)` and one mole of a monobasic acid of equivalent mass 74. What is the

2 Answers 6 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
The reaction is :
`M_(2)CO_(3)+ 2HCl to 2Mcl + H_(2)O + CO_(2)`
Number of moles of `CO_(2)` = Number of moles of `M_(2)CO_(3)`
`0.01186 = ("Mass")/("Molar mass of" M_(2)CO_(3))= (1)/("Molar mass of"M_(2)CO_(3))`
`therefore` Molar mass of `M_(2)CO_(3) = (1)/(0.01186) = 84.3 g mol^(-1)`

5 views Answered 2023-02-05 15:29