Equal volumes of following solutions are mixed. In which case the pH of resulting solution will be average value of pH of two solutions?
A. Aqueous `HCl` of `pH=2` aqueous `NaOH` of `pH=12`
B. Aqueous `HCl` of `pH=2`, aqueous `HCl` of `pH=4`.
C. Aqueous `HCl` of `pH=2` aqueous `NaOH` of `pH=10`
D. Aqueous `CH_(3)COOH` of `pH=5` aqueous `NH_(3)` of `pH=9.[K_(a)(CH_(3)COOH)=K_(b)(NH_(3))]`

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(A) `[H^(+)]=10^(-2)` and `[OH^(-)]=10^(-2)`
`H^(+)+OH^(-)rArr H_(2)O`
This leads complete neutraltisation.
so `pH=7=(2+12)/(2)`
(D) `[H^(+)]=10^(-5)` and `[OH^(-)]=10^(-5)`
`[H^(+)]+[OH^(-)]=H_(2)O`
This leads complete neutralisation.
so `pH=7=(5+9)/(2)`

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