Equal volumes of following solutions are mixed, in which case the pH of resulting solution will be average value of pH of two solutions.

Question

Equal volumes of following solutions are mixed, in which case the pH of resulting solution will be average value of pH of two solutions.

Equal volumes of following solutions are mixed, in which case the pH of resulting solution will be average value of pH of two solutions.
A. pH=2 HCl and pH=12 NaOH
B. pH=2 HCl and pH=4 HCl
C. pH=2 HCN and pH= 12 NaOH (`k_a` for HCN=`10^(-10)`)
D. pH=5 `CH_3COOH` and pH=9 `NH_(3(aq.)),K_a(CH_3COOH)=K_b(NH_(3_(aq)))`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - A,D
(A)`pH=2 HCl` so [HCl]=`10^(-2)`
pH=12 NaOH so [NaOH]=`10^(-2)`
Hence pH of mixture =7 (neutral )
(D)pH=5 `CH_3COOH` and pH=9 `NH_3` (aq), both must be of equal concentrations as `pK_a=pK_b`.Hence pH=pOH only if concentration are equal so on mixing equal volume we will get `CH_3COONH_4` salt solution and its pH is given is given by
`pH=1/2(pK_w+pK_a-pK_b)=7`