25mL of 3.0 M HCI are mixed with 75 of 4.0 M HCI. If the volumes are volumes are aditive, the molarity of the final solution will be :

Question

25mL of 3.0 M HCI are mixed with 75 of 4.0 M HCI. If the volumes are volumes are aditive, the molarity of the final solution will be :

25mL of 3.0 M HCI are mixed with 75 of 4.0 M HCI. If the volumes are volumes are aditive, the molarity of the final solution will be :
A. 4.0 M
B. 3.75 M
C. 4.25 M
D. 3.5 M

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - b
If the two solutions containing the same solute are mixed, the molarity of the resulting solution is given as :
`M_(3)V_(3)=M_(1)V_(1)+M_(2)V_(2)`
`M_(3)=(M_(1)V_(1)+M_(2)V_(2))/V_(3)=(M_(1)V_(1)+M_(2)V_(2))/((V_(1)+V_(2)))`
`=((3.0M)xx(25mL)+(4.0M)xx(75mL))/((25+75)mL)`
=3.75 M

5 views Answered 2023-02-05 15:29