The alternating current in a circuit is given by `I = 50sin314t`. The peak value and frequency of the current are

Question

The alternating current in a circuit is given by `I = 50sin314t`. The peak value and frequency of the current are

The alternating current in a circuit is given by `I = 50sin314t`. The peak value and frequency of the current are
A. `I_(0)`=25 A and f=100Hz
B. `I_(0)`=50 A and f=50 Hz
C. `I_(0)` = 50 A and f=100 Hz
D. `I_(0)`=25 A and f=50 Hz

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
From standard equation, we have
`I= I_(0)sinomegat`...............(i)
Given, I=50sin314t ..............(ii)
Comparing Eqs. (i) and (ii), we get
`I_(0)`= 50 A, `omega = 2pif` = 314 `rArr f=314/(2 xx 3.i14) = 50 Hz`

5 views Answered 2023-02-05 15:29