An alternating current in a circuit is given by l = 20 sin ( 100`pi`t + ` 0.05pi `) A. The rms value and the frequency of current respectively are

Question

An alternating current in a circuit is given by l = 20 sin ( 100`pi`t + ` 0.05pi `) A. The rms value and the frequency of current respectively are

An alternating current in a circuit is given by l = 20 sin ( 100`pi`t + ` 0.05pi `) A. The rms value and the frequency of current respectively are
A. 10 A and 100 Hz
B. 10 A and 50 Hz
C. 10`sqrt 2`A and 50 Hz
D. 10`sqrt 2`A and 100 Hz

Monjur Alahi

13 views

2025-01-04 04:42

1 Answers

Related Questions

If an alternating voltage is represented as `E=141 sin (628 t)`, then the rms value of the voltage and the frequency are respectively

2 Answers 8 Views

The rms value and frequency of an ac current are 5A and 50 Hz respectively. The value of the current after `1/300s` from the time when its value becom

2 Answers 5 Views

In an ac circuit alternating voltage E=`200sqrt2` sin 100t volt is connected to a capacitor of capacity`1muF`. The rms value of the current in the cir

2 Answers 5 Views

a) The peak voltage of an AC supply is 300 V. What is the rms voltage? b) The rms value of current in an AC circuit is 10A. What is the peak current?

2 Answers 5 Views

The peak value of an alternating current is `5 A` and its frequency is `60 Hz`. Find its rms value. How long will the current take to reach the peak v

2 Answers 6 Views

In an AC circuit , an alternating voltage e = 200``sin 100t V is connected to a capacitor of capacity `1mu F` . The rms value of the current in the ci

2 Answers 5 Views

An alternating emf given by equation `e=300sin(100pi)t V` is applied to a resistance `100 Omega`. The rms current through the circuit is (in amperes).

2 Answers 5 Views

Assertion The average value of alternating emf is 63.39% of the peak value . Reason The rms value of alternating emf is70.72% of peak value

2 Answers 8 Views

Find the principal values of the following (i) `sin^(-1) (sin 1)` (ii) `sin^(-1) (sin 2)` (iii) `sin^(-1) (sin 10)` (iv) `sin^(-1) (sin 20)` (v) `sin^

2 Answers 5 Views

The peak value of an alternating current is 5A and its frequency is 60Hz. Find its rms value. How long will the cukrgrenQt current IS 5 A and its freq

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
I = 20 sin(100`pi`t + `0,05pi`)
`therefore` `underset(rms)(I)` = 20 / `sqrt 2 ` = 10`sqrt 2` A
`omega` = `100pi` `adr` f = 50Hz

13 views Answered 2023-02-05 15:29