If the equation of alternating emf is V = 200 sin 300t, then for a circuit containing R = 100 `Omega` and L = 800 mH, the peak value of current will b

Question

If the equation of alternating emf is V = 200 sin 300t, then for a circuit containing R = 100 `Omega` and L = 800 mH, the peak value of current will b

If the equation of alternating emf is V = 200 sin 300t, then for a circuit containing R = 100 `Omega` and L = 800 mH, the peak value of current will be in ampere :
A. 0.77
B. `2.0`
C. 1.5
D. 1.83

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`X_L=(300xx800)/1000`=240
R=100
`i=V/Z =200/sqrt(100^2 + 240^2)`

4 views Answered 2023-02-05 15:29