An alternating emf of 200 V, 50 Hz is applied a circuit containing a resistance of 100 `Omega` and inductance of 0.1 H in series. The powerr dissipate

Question

An alternating emf of 200 V, 50 Hz is applied a circuit containing a resistance of 100 `Omega` and inductance of 0.1 H in series. The powerr dissipate

An alternating emf of 200 V, 50 Hz is applied a circuit containing a resistance of 100 `Omega` and inductance of 0.1 H in series. The powerr dissipated in the circuit is
A. 463 W
B. 364 W
C. 634 W
D. 346 W

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

An L-C_R series circuit is joined to a source of alternating e.m.f. If `R=9 Omega, X_(L)=28 Omega, X_(C)=16 Omega`, then the impedance of the circuit

2 Answers 4 Views

An inductance of `0.4/(pi)` henry and a resistace of `30 Omega` are joined in series. If an alternating e.m.f. of 200 V, 50 Hz is applied to their com

2 Answers 4 Views

An alternating e.m.f. of 200V,50Hz is applied to a series L-R circuit. If `L=(0.4)/(pi)` henry and `R=30 Omega`, then the impendance of the circuit an

2 Answers 4 Views

An alternating e.m.f. `E=10sqrt(2) sin omega` volt is applied to a circuit containing a pure inductance L and a resistance and voltage acros the resis

2 Answers 5 Views

An alternating e.m.f. given by e=200 sin 50 t is applied to a circuit containing only a resistance of `50 Omega`. What is the value of r.m.s. current

2 Answers 4 Views

An alternating emf, e=300 sin100`pit` volt, is applied to a pure resistance of 100 `Omega`. The rms current through the circuit is

2 Answers 5 Views

An inductance of 100 mH and a resistance of 100 `Omega` are connected in series and an alternating emf of peak value 100 V, 50 Hz is applied across th

2 Answers 5 Views

In LCR series circuit , an alternating emf e and current `i` are given by the equations `e = 100sin (100 t) ` volt . `i=100 sin (100 t + (pi)/(3))` mA

2 Answers 5 Views

An alternating supply of 220 V is applied across a circuit with resistance `22 Omega` and impedance `44 Omega`. The power dissipated in the circuit is

2 Answers 5 Views

If the equation of alternating emf is V = 200 sin 300t, then for a circuit containing R = 100 `Omega` and L = 800 mH, the peak value of current will b

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`X__(L)=2pifL`
`=2xx3.14xx50xx0.1`
`=31.4Omega`
`Z=sqrt(R^(2)+X_(L)^(2))`
`=sqrt((100)^(2)+(31.4)^(2))`
`=sqrt(10000+985.9)=104.8Omega`
`overline(P)=eIcosphi`
`=e*(e)/(Z)*(R)/(Z)`
`=(200xx200xx100)/(104.8xx104.8)=364W`

4 views Answered 2023-02-05 15:29