An L-C_R series circuit is joined to a source of alternating e.m.f. If `R=9 Omega, X_(L)=28 Omega, X_(C)=16 Omega`, then the impedance of the circuit

Question

An L-C_R series circuit is joined to a source of alternating e.m.f. If `R=9 Omega, X_(L)=28 Omega, X_(C)=16 Omega`, then the impedance of the circuit

An L-C_R series circuit is joined to a source of alternating e.m.f. If `R=9 Omega, X_(L)=28 Omega, X_(C)=16 Omega`, then the impedance of the circuit will be
A. `10 Omega`
B. `15 Omega`
C. `20 Omega`
D. `30 Omega`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`Z = sqrt(R^(2)+(X_(L)-X_(C))^(2)) = sqrt(9^(2)+(28-16)^(2)) = 15 Omega`.

4 views Answered 2023-02-05 15:29