Concentration of `SO_(4)^(2-)` ions in a solution prepared by mixing `100 ml 0.1 M BaCl_(2)` and `400 ml 0.2 M Na_(2)SO_(4)`.

Question

Concentration of `SO_(4)^(2-)` ions in a solution prepared by mixing `100 ml 0.1 M BaCl_(2)` and `400 ml 0.2 M Na_(2)SO_(4)`.

Concentration of `SO_(4)^(2-)` ions in a solution prepared by mixing `100 ml 0.1 M BaCl_(2)` and `400 ml 0.2 M Na_(2)SO_(4)`.
A. `(8)/(50)M`
B. `(7)/(50)M`
C. `(7)/(40)M`
D. `(1)/(25) M`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

A `0.004M` solution of `Na_(2)SO_(4)` is isotonic with a `0.010M` solution of glucose at same temperature. The apparent degree of dissociation of `Na_

2 Answers 4 Views

Osmotic pressure of a solution obtained by mixing `100 mL` of 1.4% solution of urea (mol mass = 60) and `100 mL` of `3.42%` of cane sugar solution (mo

2 Answers 5 Views

500 mL of 0.250 M `Na_(2)SO_(4)` solution is treated with 15.00 g of `BaCl_(2)`. Moles of `BaSO_(4)` formed are

2 Answers 6 Views

`3 BaCl_(2) + 2Na_(3)PO_(4) to Ba_(3)(PO_(4))_(2)+6NaCl` Maximum amount of `Ba_(3)(PO_(4))_(2)` formed when 2 moles each of `Na_(3)PO_(4)` and `BaCl_(

2 Answers 4 Views

50 mL solution of `BaCl_(2)` (20.8% w//v) and 100 mL solution of `H_(2)SO_(4)` (9.8% w//v) are mixed (Ba = 137, Cl = 35.5, S=32) `BaCl_(2) + H_(2)SO_(

2 Answers 5 Views

Assertion : Oxidation of `Na_(2)SO_(3)` is not caused by air but in the presence of `Na_(3)AsO_(3).` Reason : `Na_(3)AsO_(3)` can be oxidised by air.

2 Answers 6 Views

A solution is obtained by mixing 200 ml 1 M `CaCl_(2)`, 300 ml 2 M `Na_(2)SO_(4)` and 500 ml 1 M `BaCl_(2)` then which of the following is correct for

2 Answers 5 Views

Concentration of `Cl^(-)` ions in a solution obtained by mixing `600 ml` of `0.1 M CaXl_(2)` and `400 ml` of `0.4 M AlCl_(3)`.

2 Answers 4 Views

Calculte the osmotic pressure os a solution obtained by mixing 100 mL of 4.5% solution of urea (mol. Mass =60) and 100 mL pf 3.42% solution of cane su

2 Answers 5 Views

Enthalpies of solution of `BaCl_(2)(s)` and `BaCl_(2).2H_(2)O(s)` are `-20 kJ//"mole"` and `8.0kJ//"mole"` respectively. Calculate heat of hydration o

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - B
`{:(BaCl_(2),+,Na_(2) SO_(4),rarr,BaSO_(4),+,2NaCl,),(0.01 "mole",,0.08 "mole",,,,,),(-,,0.07 "mole",,underset(PPt darr)(0.01 "mole"),,0.01 "mole",):}`
`{:(Na_(2)SO_(4),rarr,2Na^(+),+,SO_(4)^(2-),),(0.07 "mole",,-,,-,),(-,,0.14 "mole",,0.07 "mole",):}`
`[SO_(4)^(2-)] = (n_(SO_(4)^(2-)))/(V_(1) + V_(2)) = (0.07)/(0.5) = (7)/(50) M`