Enthalpies of solution of `BaCl_(2)(s)` and `BaCl_(2).2H_(2)O(s)` are `-20 kJ//"mole"` and `8.0kJ//"mole"` respectively. Calculate heat of hydration o

Question

Enthalpies of solution of `BaCl_(2)(s)` and `BaCl_(2).2H_(2)O(s)` are `-20 kJ//"mole"` and `8.0kJ//"mole"` respectively. Calculate heat of hydration o

Enthalpies of solution of `BaCl_(2)(s)` and `BaCl_(2).2H_(2)O(s)` are `-20 kJ//"mole"` and `8.0kJ//"mole"` respectively. Calculate heat of hydration of `BaCl_(2)(s)`.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

heat of formation of ` H_(2)O is -188 kJ // mol and H_(2)O_(2) is -286 kJ // mol` . The enthaply change for the reaction ` 2H_(2)O_(2) to 2H_(2 )O+O_(

2 Answers 6 Views

the enthalpy of dissolution of `BaCl _(2) (s) and BaCl_(2). 2H_(2)O(s) are - 20 . 6 and 8.8 kJ // mol ` respectively. The enthalpy of hydration for `B

2 Answers 8 Views

one mole of an anydrose salt AB dissolves in water with the evolution of `21.0mol^(-1)` of heat. If the heat of hydration of AB is `-29.4 J mol^(-1)`

2 Answers 4 Views

Calculate the enthalpy change for the following reaction: `CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(l)` given, enthalpies of formation of `CH_(4),CO_(2)

2 Answers 9 Views

For the reaction `2NO(g)+O_(2)(g)to2NO_(2)g` Calculate `DeltaG` at 700K when enthalpy and entropy changes are `-113.0kJ" "mol^(-1) and `-145J" "K^(-1)

2 Answers 5 Views

Calculate the enthalpy of the reaction `SnO_(2)(s)+2H_(2)(g)toSn(s)+2H_(2)O(l)` given that , bond enthalpies of formation of `SnO_(2)(s)` and `H_(2)O(

2 Answers 4 Views

One mole of anhydrous `MgCl_(2)` dissolves in water and librates `25 cal//mol` of heat. `Delta H_("hydration")` of `MgCl_(2)=30 cal//mol`. Heat of dis

2 Answers 7 Views

Heat of formation of `CH_(4)` are: If given heat: `C(s)+ O_(2)(g) rarr CO_(2) (g) " "DeltaH =-394 KJ` `2H_(2) (g)+ O_(2)(g) rarr 2H_(2)O(l) rarr 2H_(2

2 Answers 5 Views

Determine enthalpy of formation for `H_(2)O_(2)(l)` , using the listed enthalpies of reactions: `N_(2)H_(4)(l) + 2H_(2)O_(2)(l) rarr N_(2)(g) + 4H_(2)

2 Answers 5 Views

When one mole of zinc combines with sulphuric acid 445 kJ of heat is liberated and when a mole of copper is liberated from blue vitriol 235 kj of heat

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - `-28kJ//"mole"`

4 views Answered 2023-02-05 15:29