Two particles are projected horizontally with same speed `30 m//s` but in opposite directions from same height at time `t = 0`. Calculate angle betwee

Question

Two particles are projected horizontally with same speed `30 m//s` but in opposite directions from same height at time `t = 0`. Calculate angle betwee

Two particles are projected horizontally with same speed `30 m//s` but in opposite directions from same height at time `t = 0`. Calculate angle between velocity vectors of particles at time `t = 3s`.
A. `0^(@)`
B. `30^(@)`
C. `60^(@)`
D. `90^(@)`

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`cos theta = (vec(v)_(1) . vec(v)_(2))/(v_(1) v_(2))`
`= ((30hat(i) - 30 hat(j)))/(30 sqrt2).((-30 hat(i) - 30 hat(j)))/(30 sqrt2) = 0`
`rArr theta = 90^(@)`

6 views Answered 2023-02-05 15:29