The maximum amount of `BaSO_(4)` precipitated on mixing `BaCl_(2)` (0.5 M) with `H_(2)SO_(4)` (1M) will correspond to
The maximum amount of `BaSO_(4)` precipitated on mixing `BaCl_(2)` (0.5 M) with `H_(2)SO_(4)` (1M) will correspond to
A. 0.5 M
B. 0.1M
C. 1.5M
D. 2.0M
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Correct Answer - A
0.5 m `BaCl_(2)` will react with 0.5 M `H_(2)SO_(4)`
`BaCl_(2)+H_(2)SO_(4) rarr BaSO_(4)+2HCl`
Here `BaCl_(2)` is a limiting reactant
`:. BaSO_(4)` produced `=0.5 M`.
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