Dissolving 120g of urea (mol wt 60) in 100 g of water gave solution of density `1.158g//mL`. The molarity of the solution is

Question

Dissolving 120g of urea (mol wt 60) in 100 g of water gave solution of density `1.158g//mL`. The molarity of the solution is

Dissolving 120g of urea (mol wt 60) in 100 g of water gave solution of density `1.158g//mL`. The molarity of the solution is
A. `1.78 M`
B. `2.00M`
C. `2.05M`
D. `2.22M`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Related Questions

By dissolving 0.35 mole of sodium chloride in water, 1.30L of salt solution is obtained. The molarity of the resulting solution should be reported as-

2 Answers 6 Views

120g of urea is present in 5L of solution, the active mass of urea is

2 Answers 6 Views

The molarity of urea (molar mass 60 g `mol^(-1)`) solution by dissolving 15 g urea in 500 `cm^(3)` of water is

2 Answers 5 Views

`6.02 xx 10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is (Avogadro constant, `N_(A) = 6.02 xx

2 Answers 8 Views

A solution of urea (mol mass `56 g mol^(-1))` boils at `100.18^(@)C` at the atmospheric pressure. If `K_(f)` and `K_(b)` for water are `1.86` and `0.5

2 Answers 5 Views

Osmotic pressure of a solution obtained by mixing `100 mL` of 1.4% solution of urea (mol mass = 60) and `100 mL` of `3.42%` of cane sugar solution (mo

2 Answers 5 Views

Calculte the osmotic pressure os a solution obtained by mixing 100 mL of 4.5% solution of urea (mol. Mass =60) and 100 mL pf 3.42% solution of cane su

2 Answers 5 Views

A solution of HCI is prepared by dissolving 5.5 g HCI in 200 g ehanol. The density of the solution is 0.79 g `mL^(-1)` Molarity of solution is :

2 Answers 5 Views

The density of a solution prepared by dissolving 120 g of uree (molar mass = 60 u) in 1000 g of water is 1.15 g/mL The molarity of solution is:

2 Answers 7 Views

Dissolveing 120 g of urea (molar mass = 60) in 1000 g of water gave a solution of density 1.15g/mL. The molarity of the solution is :

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Total mass of solution = (1000+120) = 1120 g
Total volume of solution `= ("Mass")/("Density")=(1120)/(1.15)`
`= 973.91 mL`
Molarity `M_(f)=(W)(m)xx(1000)/(V(mL))`
`=(120)/(60)xx(1000)/(973.91)=2.05 M`

5 views Answered 2023-02-05 15:29