120g of urea is present in 5L of solution, the active mass of urea is
120g of urea is present in 5L of solution, the active mass of urea is
A. 0.2
B. 0.06
C. 0.4
D. 0.88
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Correct Answer - C
Active mass = concentration = M
` :. M=W_(2)/(M_(2) xx V (L))=120/(60 xx 5)=12/30=0.4`
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