Dissolveing 120 g of urea (molar mass = 60) in 1000 g of water gave a solution of density 1.15g/mL. The molarity of the solution is :

Question

Dissolveing 120 g of urea (molar mass = 60) in 1000 g of water gave a solution of density 1.15g/mL. The molarity of the solution is :

Dissolveing 120 g of urea (molar mass = 60) in 1000 g of water gave a solution of density 1.15g/mL. The molarity of the solution is :
A. `1.78 M`
B. `2.00 M`
C. `2.05 M`
D. `2.22 M`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - b,c
Total mass of solution
=1000+120=120=1120 g
Total volume of solution
`="Mass"/"Density"=((1120g))/((1.15"g mL"^(-1)))`
=973.91.= mL
`"Molarity(M)"=("Gram moles of solute")/("Volume of solution in liters")`
`=((120g//60"g mol"^(-1)))/((973.91//1000L))=2.05 "mol L"^(-1)`
=2.05 M.

5 views Answered 2023-02-05 15:29